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fact that the wide-lane phase has a wavelength of approximately 86cm can simplify integer ambiguity resolution in di erential GPS applications The pseudorange estimates can be processed similarly yielding 2 1 w 1 2 2 1 + n 1 2 w w 1 2 1 2 n n = + Ecm + Ia + 1 + 2 1 2 = + Ecm Ia + (8107) (8108)

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The code observables provide a noisy but complete measurement of the pseudorange while the phase observables provide a relatively noise-free but biased measurement of the pseudorange Carrier-smoothing is one approach that has been to achieve an unbiased and smooth pseudorange estimate In this section, we present the approach for non-di erential wide-lane phase and narrow-lane code observables This approach can also be used directly with L1 code and phase for a single frequency receiver, but the designer should be careful due to the issue of code-carrier divergence Eqns (8106) and (8108) have the form 2 1 + n 1 2 ( 1 2 ) w = = r + n1 r + C + n2 (8109) (8110)

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12 Each specific complex impedance value defined in the form R + jXL (a) corresponds to a specific point in the RL plane (b) corresponds to a specific inductive reactance (c) corresponds to a specific resistance (d) All of the above are true 13 A vector is defined as a mathematical quantity that has (a) magnitude and direction (b) resistance and inductance (c) resistance and reactance (d) inductance and reactance 14 In an RL circuit, as the ratio of inductive reactance to resistance (XL/R) decreases, the phase angle (a) increases (b) decreases (c) stays the same (d) becomes alternately positive and negative 15 In a circuit containing inductive reactance but no resistance, the phase angle is (a) constantly increasing (b) constantly decreasing (c) equal to 0 (d) equal to 90 16 If the inductive reactance and the resistance in an RL circuit are equal (as expressed in ohms), then what is the phase angle (a) 0 (b) 45 (c) 90 (d) It depends on the actual values of the resistance and the inductive reactance 17 In Fig 13-14, the impedance shown is which of the following (a) 80 (b) 90 (c) 90 + j80 (d) 80 + j90 18 Note that in the diagram of Fig 13-14, the R and XL scale divisions are of different sizes The phase angle can nevertheless be determined It is (a) about 50 , from the looks of it (b) 48 , as measured with a protractor

where r = + Ecm + Ia , n1 = n 1 + n 2 , n2 = w 1 w 2 and 1 2 1 2 C C = (N1 N2 ) w Note the C is a constant and that w is an integer Eqns (8109 8110) are (again) of the exact form considered in Example 54; therefore, C can be estimated as 1 Ck = Ck 1 + k w w (k) n (k) Ck 1